You cant; unless either point has a conversion operator, or subpoint has a conversion constructor, in which case the object types can be converted with no need for a cast. https://edu.csdn.net/skill/algorithm?utm_source=AI_act_algorithm, https://blog.csdn.net/m0_64538406/article/details/129271841, Small Tricks Learned from Professor Tri Phams CS2B Class at Foothill College. No, there is no built in conversion for this. If anything, the default constructor of the DerivedType would be invoked, followed by an attempt to invoke an assignment operator, if one existed with the BaseType as the argument. The code you posted using as will compile, as I'm sure you've seen, but will throw a null reference exception when you run it, because myBaseObject as DerivedClass will evaluate to null, since it's not an instance of DerivedClass. The content must be between 30 and 50000 characters. C++ Explicit Conversion. instance of a derived class. Why would one create a base class object with reference to the derived class? No special syntax is necessary because a derived class always contains all the members of a base class. In my example the original class is called Working. Powered by Octopress, Slow build on compact framework projects , iOS User Interfaces: Storyboards vs. NIBs vs. When function is declared as virtual in the base class, then the corresponding functions in the derived class will be declared as virtual too. derived class, hence there is no way to explicitly perform the cast. I ended up making a static property in Global.asax.cs and assigning the configured mapper to it during Application_Start. How do you change a boolean value in Java? 2. One solution is to make operator= virtual and implement it in each derived class. When function is declared as virtual in the base class, then the corresponding functions in the derived class will be declared as virtual too. You're going to get a null ref exception on the last line. However, a base class CANNOT be used This might be at the issue when attempting to cast and receiving the noted error. The dynamic_cast function converts pointers of base class to pointers to derived class I don't really like this idea, so I'd like to avoid it if possible. The following example demonstrates the use of the dynamic_castoperator: #include
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